Answer:
-4,8
Step-by-step explanation:
(This is more of a wordy explanation, incase you don't understand how to do the problem, instead of just giving the answer right away.)
Formula: ax2 + bx + c
x2 + 4x - 32 = 0
Find a pair of numbers that multiply to c and add to b. In this case, which numbers multiply to -32 (c) and add to 4 (b)?
First let's figure out which two numbers multiply to 32 (8 x 4).
BUT, how do we get to -32? Easy! (-8 x 4) and (-4 x 8) both equal to -32, but we need the one that can also add to 4. (-4 + 8 = 4)
-4 x 8 = -32
-4 + 8 = 4
We now have our numbers and can start factoring.
1. Plug in -4 and 8 into the equation:
x2_-4_ + 4x _+8_- 32 = 0
2. Re-write it as so:
(x2 - 4x) + (8x - 32)
3. Factor each individually, taking out as much as you can:
Let's start with (x2 - 4x) first.
We can take 2x out of the equation which will give us: (x - 2)
Now lets do (8x - 32).
We can take 8 out of the equation which will give us: (x - 2)
We are now left with (x - 2) + (2x + 8)
You are done!
(Here's what it should look like on a piece of paper):
x2 + 4x - 32 = 0
-4 x 8 = -32
-4 + 8 = 32
(x2 - 4x) + (8x - 32)
2x (x2 - 4x) + 8 (8x - 32)
(x - 2) (x - 2)
Final Answer:
(x - 2) (2x + 8)
I hope this helped you understand it a bit better! :)
It's honestly very straight forward. The way I wrote it made it look so complicated lol. I was just giving a detailed explanation. Also, the school system will most likely make you use the ax2 + bx + c formula.
