Answer:
1.7 (units).
Step-by-step explanation:
1) if the point A has (-0.25;5) and the equation of the given line is -x+2y=14 (Ax+By+C=0), then the required distance can be calculated according to the formula:
[tex]d=\frac{Ax_0+By_0+C}{\sqrt{A^2+B^2} }[/tex] , where A, B and C belong to the given line, x₀, y₀ - coordinates of the given point;
2) A=-1, B=2, C=-14 and x₀=-0.25, y₀=5, then according to the formula above:
[tex]d=|\frac{0.25+5*2-14}{\sqrt{4+1}}|=\frac{3.75}{\sqrt{5}}=\frac{3.75}{2.2}=1.7[/tex]
