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The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).

Respuesta :

Answer:

5.9405*10^14 Hz

Explanation:

Remember the equation c=v*λ

v=frequency

λ=wavelength

By manipulating the equation, we can get it in terms of frequency:

c/λ=v

Now convert wavelength to meters (1nm=m*10^-9)

5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)

Use the manipulated equation:

(3.00*10^8)/(5.05*10^-7), which yields:

5.9405*10^14 Hz (or s^-1)

The frequency of the photon will be "[tex]5.9405\times 10^{14} \ Hz[/tex]".

According to the question,

Wavelength,

  • [tex]\lambda = 505 \ nm[/tex]

or,

          [tex]= 5.05\times 10^{-7} \ m[/tex]

As we know the equation,

→ [tex]c = v\times \lambda[/tex]

or,

→ [tex]v = \frac{c}{\lambda}[/tex]

By putting the values, we get

     [tex]= \frac{3.00\times 10^8}{5.05\times 10^{-7}}[/tex]

     [tex]= 5.9405\times 10^{14} \ Hz[/tex]

Thus the above answer is right.

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