A steel plate has the form of one-fourth of a circle with a radius of 54 centimeters. Two two-centimeter holes are drilled in the plate, positioned as shown in the figure. Find the coordinates of the center of each hole.

Respuesta :

top hole

x = 38 cos 60

y = 38 sin 60

bottom hole

x = 38 cos 30

y = 38 sin 30

The coordinate of holes is (43.3, 25) and (25, 43.3).

Circle

It is a special kind of ellipse whose eccentricity is zero and foci are coincident with each other. It is a locus of a point drawn at an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

Given

A steel plate has the form of one-fourth of a circle with a radius of 54 centimeters.

Two 2 centimeter holes are drilled in the plate.

To find

Two 2 centimeter holes are drilled in the plate, positioned.

How to find the position of holes?

Holes are at 50 cm from the center at an angle of 30 and 60 degrees.

So the coordinate will be given by

[tex]\rm x = r\ cos \theta \ \ \ \ \ \ \ \ y = r\ sin \theta[/tex]

Then for the first hole r = 50, at 30 degrees,

[tex]\begin{aligned} & \rm x = r\ cos \theta \ \ \ \ \ \ \ \ & \rm y = r\ sin \theta\\& \rm x = 50 *cos30 \ \ \ \ \ \ \ \ & \rm y = 50 sin30\\& \rm x = 43.3 \ \ \ \ \ \ \ \ & \rm y = 25\\\end{aligned}[/tex]

For the second hole r = 50, at 30 degrees,

[tex]\begin{aligned} & \rm x = r\ cos \theta \ \ \ \ \ \ \ \ & \rm y = r\ sin \theta\\& \rm x = 50 *cos60 \ \ \ \ \ \ \ \ & \rm y = 50 sin60\\& \rm x = 25 \ \ \ \ \ \ \ \ & \rm y = 43.3\\\end{aligned}[/tex]

Thus the coordinate of holes is (43.3, 25) and (25, 43.3).

More about the circle link is given below.

https://brainly.com/question/11833983

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