The large division mathematical problem can be solved using partial
quotient;
The methods that could be used to find the quotient are;
B. Subtract (30 × 12) from 468to get 108. Subtract (9 × 12) from 108 to have
0 remainder.
C. Subtract (20 × 12) from 468 to get 228. Subtract (10 × 12) from 228 to get
108. Subtract (3 × 12) from 108 to get 72. Subtract 6 × 12 from 72 to get a 0
remainder.
Reason:
The division of 468 by 12 using partial quotient gives;
12|[tex]\overline{468}[/tex]
[tex]{}[/tex] -360 ← 30 × 12
[tex]{}[/tex] 108
[tex]{}[/tex] -108 ← 9 × 12
[tex]{}[/tex] 0
Therefore, the quotient = 30 + 9 = 39
Therefore, option B. can be used to find the quotient;
Option B: Subtract (30 × 12) from 468; 468 - 30 to get 108. Subtract (9 ×
12) from 108 to have 0 remainder.
The method in option C which is expressed as follows;
468 - 20 × 12 = 228
228 - 10 × 12 = 108
108 - 3 × 12 = 72
72 - 6 × 12 = 0
Therefore, option is C. could be used and the statement is expressed as follows;
Subtract (20 × 12) from 468 to get 228. 468 - (20 × 12) = 228
Subtract (10 × 12) from 228 to get 108. 228 - (10 × 12) = 128
Subtract (3 × 12) from 108 to get 72. 108 - (3 × 12) = 72
Subtract (6 × 12) from 72 to get a 0 remainder.
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