Respuesta :
Rate of change is the change in a quantity with regards to another quantity
(a) The change in the solution in the tank after 1 minute is [tex]\underline{-3\frac{7}{15} \ L}[/tex]
(b) The change in the volume after 15 seconds is [tex]\underline{-\dfrac{13}{15} \ L}[/tex]
(c) The solution in the tank decreases by [tex]-\dfrac{13}{15} \ L[/tex] in 15 seconds
Reason:
The given parameters of the solution in the tank are;
The rate at which the solution enters the tank, V = [tex]16\frac{3}{4}[/tex] liters per minute
The rate at which the solution leaves the tank = [tex]19\frac{4}{5}[/tex] liters per minute
(a) The expression that represents the change in volume in the tank is given as follows;
[tex]16\frac{3}{4} \ L - 19\frac{4}{5} \ L = -3\frac{7}{15} \ L[/tex][tex]-3\frac{7}{15} \ L[/tex]
The change in the volume of solution in the tank after 1 minute is [tex]-3\frac{7}{15} \ L[/tex]
(b) 15 seconds = 0.25 × 1 minute
Therefore, the change in the volume after 15 seconds is [tex]-3\frac{7}{15} \ L \times 0.25 = -\dfrac{13}{15} \ L[/tex]
(c) The change in the volume of solution in the tank after 15 seconds is a decrease in the volume of solution in the tank by [tex]-\dfrac{13}{15} \ L[/tex]
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