Respuesta :

yashjaglan012

u=0 m/s

h=2.5m

Using kinematic eq:

[tex] {v}^{2} - {u}^{2} = 2gh \\ {v}^{2} - {0}^{2} = 2gh \\ v = \sqrt{2gh} \\ v = \sqrt{2 \times 10 \times 2.5} \\ v = \sqrt{50} \\ v = 7.07m/s[/tex]

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