using the substitution method Ken solves the following system of equations algebraically
2x-y=5
3x+2y=-3

which equivalent equation could ken us

a 3x+2 (2x-5)=-3)
b 3 (y+5/2) +2y=-3
c 3+2( 5-2x)=-3
d 3 5/2-y) +2y=-3