The launch of projectiles allows to find the result for the width of the river is 6m
Projectile launching is an application of kinematics to the miller of bodies near the surface, in this case there is no acceleration on the x-axis and on the y-axis (vertical) the acceleration is the gravity acceleration, directed downward.
The reference system is a coordinate system with respect to which measurements are made, in this case the x-axis is horizontal with a positive direction in the direction of movement and the y-axis is vertical with a positive upward direction.
They indicate that Joyner goes horizontally, so its velocity is horizontal
(vₓ = 9.37 m / s) and its initial vertical velocity is zero, it also indicates that the height between the two parts of the river is I = 2 m, let's find the jump time
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
0 = y₀ - ½ g t²
t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]
t = [tex]\sqrt{ \frac{2 \ 2}{9.8 } }[/tex]
t = 0.639 s
In the attachment we can see a diagram of the movement.
We look for the horizontal distance that corresponds to the width of the river
x = vₓ t
x = 9.37 0.639
x = 6 m
In conclusion, using the launch of projectiles we can find the result for the width of the river is 6m
Learn more here: brainly.com/question/6287497
