Respuesta :

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Answer:

tan A = opp

adj

tan G = EF

3

from Pythagoras theorem,

EF² + 3² = (√24)²

EF² + 9 = 24

EF² = 15

EF = √15

then,

tan G = √15

3

therefore tan G = √15/3

DᴀʀᴋPᴀʀᴀᴅᴏx

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's solve :

by using Pythagoras theorem :

  • EF² = EG² - GF²

  • EF² = [tex]{\sqrt{}{24}}^{2}[/tex] - 3²

  • EF² = 24 - 9

  • EF² = 15

  • EF = [tex]{\sqrt{}{15}}[/tex]

now,

  • [tex] \tan(G) = \dfrac{ \sqrt{15} }{3} [/tex]

  • [tex]\tan(G) = \dfrac{3.873}{3} [/tex]

  • [tex]\tan(G) = 1.291[/tex]

  • [tex]\tan(G) \approx1.29[/tex]
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