The angular velocity at 0.200 s is 2.7 rad/s . The blade turned 0.086 revolutions in 0.200 s. The tangential velocity at 0.200 s is 1.01 m/s.
Given that the radius = 0.750 m /2 = 0.375 m
Using the formula;
v = u + at
v = ?
u = 1.57 rad/s
t = 0.200 s
a = 5.65 rad/s²
Hence, v = 1.57 rad/s + (5.65 rad/s²) 0.200 s
v = 2.7 rad/s
Given that;
ω = θ/t
Where;
ω = angular velocity
θ = angle turned
t = time taken
2.7 rad/s = θ/0.200 s
θ = 2.7 rad/s × 0.200 s
θ = 0.54 rad
If 1 revolution = 6.283 radians
x revolutions = 0.54 radians
x = 1 revolution × 0.54 radians/6.283 radians
x = 0.086 revolutions
The tangential speed at 0.200 s is obtained from
v = ωr
ω = angular velocity
v = linear velocity
r = radius of the circular path
v = 2.7 rad/s × 0.375 m
v = 1.01 m/s
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