Help Please! It would help a lot!!!! 20 POINTS!


1. Winston grows green dragon apples. This year, he shipped $80\%$ of these apples to sell at supermarkets and kept the rest to make cider. Of all the green dragon apples he sold to the supermarkets, only $60\%$ of them were bought. If a total of $840$ green dragon apples were bought, how many green dragon apples did Winston keep to make cider?

2. Ms. Forsythe gave the same algebra test to her three classes. The first class averaged $80\%,$ the second class averaged $85\%,$ and the third $89\%.$ Together, the first two classes averaged $83\%,$ and the second and third classes together averaged $87\%.$ What was the average for all three classes combined? Express your answer to the nearest hundredth.

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Answer: This is gonna be a long one

1)Winston grows green dragon apples. This year, he shipped 80%of these apples to sell at supermarkets and kept the rest to make cider. Of all the green dragon apples he sold to the supermarkets, only 60% of them were bought. If a total of 420 green dragon apples were bought, how many green dragon apples did Winston keep to make cider?

 Call the number he shipped to the store, N

So .

60N  = 420   divide both sides by  ,60

420 / .60  = N  = 700 were shipped to the stores

But this number was  80%  of the total he grew = T

So

.80T  = 700   divide both sides by  .80

700/.80 = T  = 875

But..he kept 20% of these =   875 * .20  = 175

2)Ms. Forsythe gave the same algebra test to her three classes. The first class averaged 80%, the second class averaged 85%, and the third 89%. Together, the first two classes averaged 83%, and the second and third classes together averaged 87%. What was the average for all three classes combined? Express your answer to the nearest hundredth.

 

The average  =  total points / number of students

So....total points = average*number of students

Let the total number of students in  each class = x , y  and z

The total number of points the first class amassed  was   80x

The total number of points amased by the second class was  85y

The total number of points amassed by the third class = 89z

So...for the first two classes we have

[ 80x + 85y ] / [ x + y] = 83

80x + 85y = 83x + 83y  subtract  80x, 83y from both sides    

3x = 2y

x = 2/3y

And,,,for the second two classes we have

[ 85y + 89z ]  / [ y + z ]  =  87  

[  85y + 89z ]  = 87 [y + z]

85y + 89z = 87y + 87z      subtract  85y, 87z from both sides

2z = 2y  

y  = z

So...for the three classes.....

Total points by all three classes /  number of class members  = the average for all three classes

[ 80x + 85y  + 89z ] /  [ x + y + z ]   =

[sub for  x and z ]  

[80 (2/3)y  + 85y  + 89y]  /  [ (2/3)y  + y  + y ]  

y [ 80 (2/3)  + 85  + 89 ]  / [  y [( 2/3) + 1 + 1] ]       [cancel the y's ]

[ 80 (2/3) + 85 + 89]  [  8/3 ]

[ 160/3 + 85 + 89 ] /  [8/3] =

[ 160/3  + 255/3 + 267/3]  / [8/3]     multiply  top/bottom by 3

[160 + 255 + 267 ] / 8  =  

85.25  = average for all three classes

Step-by-step explanation:

Hope it helps

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