Answer:
5 mph
Step-by-step explanation:
A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 4 miles per hour. Find the rate of the rowing team in still water.
***
let x=rate of the rowing team in still water
x+4=rate of the rowing team with current
x-4=rate of the rowing team against current
travel time=distance/rate
..
[tex]\frac{90}{x+4} =\frac{10}{x-4}[/tex]
90x-360=10x+40
80x=400
x=5
rate of the rowing team in still water=5 mph
Answer:
x=5
Step-by-step explanation:
A rowing team rowed 90 miles while going with the current in the same amount of time as it took to row 10 miles going against the current. The rate of the current was 4 miles per hour. Find the rate of the rowing team in still water.
***
let x=rate of the rowing team in still water
x+4=rate of the rowing team with current
x-4=rate of the rowing team against current
travel time=distance/rate
90/x+4 =10/x-4
90x-360=10x+40
80x=400
x=5
rate of the rowing team in still water=5 mph
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