Respuesta :
The percentage composition by mass of the elements in the compound are:
Ai. The percentage composition by mass of Na in 3.65 g of NaF is 54.8%
Aii. The percentage composition by mass of F in 3.65 g of NaF is 45.2%
Bi. The percentage composition by mass of Zinc in the compound is 67.1%
Bii. The percentage composition by mass of Sulfur in the compound is 32.9%
Percentage composition by mass of an element in a compound can be obtained by using the following formula:[tex]Percentage = \frac{mass of Element}{mass of compound} * 100[/tex]
Ai. Determination of the percentage of Na in 3.65 g of NaF
Mass of Na = 2 g
Mass of NaF = 3.65 g
Percentage of Na =?
[tex]Percentage = \frac{mass of element }{mass of compound} * 100\\\\Percentage of Na = \frac{2}{3.65} * 100[/tex]
Percentage of Na = 54.8%
Aii. Determination of the percentage of F in 3.65 g of NaF
Mass of F = 1.65 g
Mass of NaF = 3.65 g
Percentage of F =?
[tex]Percentage = \frac{mass of element }{mass of compound } * 100\\\\Percentage of F = \frac{1.65}{3.65} * 100\\\\[/tex]
Percentage of F = 45.2%
Bi. Determination of the percentage composition of Zn in 48.72 g of the compound
Mass of Zn = 32.69 g
Mass of compound = 48.72 g
Percentage of Zn =?
[tex]Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of Zn = \frac{32.69}{48.72} *100\\\\[/tex]
Percentage of Zn = 67.1%
Bii. Determination of the percentage composition of Sulphur in 48.72 g of the compound
Mass of Zn = 32.69 g
Mass of compound = 48.72 g
Mass of S = 48.72 – 32.69 g
Mass of S = 16.03 g
Percentage of S =?
[tex]Percentage = \frac{mass of element}{mass of compound} * 100\\\\Percentage of S = \frac{16.03}{48.72} * 100\\\\[/tex]
Percentage of S = 32.9%
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