We have that the velocity of the ball when it hits the glass.Using the appropriate significant figures is
V=4.43ft/s
From the question we are told that
- Mr. Bari drops a 3 kg ball from 1 feet above the glass
- the velocity of the ball when it hits the glass
Generally the equation for the Velocity is mathematically given as
[tex]V^2=2as\\\\Therefore\\\\V=\sqrt{2*9.8*1}\\\\V=4.43ft/s[/tex]
Therefore
the velocity of the ball when it hits the glass.Using the appropriate significant figures is
V=4.43ft/s
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