Exponents and scientific notation

Answer:
Step-by-step explanation:
[tex]3) \dfrac{d^{-5}*d^{3}}{(d^{4})^{3}}=\dfrac{d^{-5+3}}{d^{4*3}}\\\\= \dfrac{d^{-2}}{d^{12}}\\\\= \dfrac{1}{d^{12 -[-2]}}\\\\=\dfrac{1}{d^{12+2}}\\\\=\dfrac{1}{d^{14}}[/tex]
Hint:
[tex]a^{m}*a^{n} =a^{m+n}\\\\\dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\(a^{m})^{n}=a^{m*n}[/tex]
4) √16 = 8 is wrong.
Because, √16 = [tex]\sqrt{2*2*2*2}=2*2=4[/tex]