A compound containing Na, C, and O is found to have 1. 06 mol Na, 0. 528 mol C, and 1. 59 mol O. What is the empirical formula of the compound?

Respuesta :

The empirical formula of the compound: [tex]Na_2CO_3[/tex]

Given:

A compound containing Na, C, and O is found to have 1. 06 mol Na, 0.528 mol C, and 1. 59 mol O.

To find:

The empirical formula of a compound.

Solution:

Let the empirical formula of the compound be =[tex]Na_xC_yO_z[/tex]

  • Moles of sodium = 1.06 mol
  • Moles of carbon = 0.528 mol
  • Moles of oxygen = 1.59 mol

For empirical formula divide all the moles of elements by the least moles of an element.

       [tex]x=\frac{1.06 mol}{ 0.528 mol}=2\\\\y=\frac{0.528 mol}{ 0.528 mol}=1\\\\z=\frac{1.59mol}{ 0.528 mol}=3\\\\[/tex]

The empirical formula of the compound: [tex]Na_2CO_3[/tex]

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