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Find the possible values of the constant k if the roots of the quadratic equation
x^2 - (k+2)x + 4 =0 are equal ​

Respuesta :

discipulus

Answer:

[tex] {b}^{2} - 4ac = 0 \\ { ( - k - 2)}^{2} - 4(1)(4) = 0\\ {k}^{2} + 4k + 4 - 4 = 0 \\ {k}^{2} + 4k = 0 \\ k(k + 4) = 0 \\ \therefore \: k = 0 \: or \: k = - 4[/tex]

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