Answer:
Point (6, -1) = (x, y)
Slope = -3
The proper linear equation is written in following form: y = mx + b (where m is slope, and b is y-intercept). Since we already have the slope, we need to find the y-intercept, b
So we plug in what we have:
y = mx + b
-1 = (-3)(6) + b, where we solve for b
-1 = -18 + b
b = 17
Finally, the equation of the line that passes through point (6, -1) and has a slope of -3 is y = -3x + 17
