Frequency is [tex]2 drop/second[/tex]
Period is [tex]0.5[/tex]
Wavelength is [tex]15 m[/tex]
Speed of propagation of wave is [tex]30m/s[/tex]
Given:
Drop on the surface of pool at the rate 120 drops per minute
Distance between third cycle and the seventh cycle is 60 m
To find :
Frequency, period and wavelength and speed of propagation of wave.
Solution:
Since, frequency is number of cycles or vibration per second
So, frequency [tex]=\frac{120 drops}{60 second} \\=2 drops/ second[/tex]
Period is reciprocal of frequency.
So, [tex]period=\frac{1}{frequency}\\ \\ =\frac{1}{2} \\=0.5[/tex]
Wavelength is distance between two consecutive cycle or vibrations.
[tex]wavelength=\frac{60}{4}\\\\ =15 m[/tex]
[tex]Speed of propagation of wave=\frac{Wavelength}{Period} \\\\=\frac{15}{0.2}\\\\=30 m/s[/tex]
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