Taking into account the stoichiometry of the reaction, 34.12 grams of LiOH are produced from 9.89 g of Li.
In first place, the balanced reaction is:
2 Li + 2 H₂O ⇒ 2 LiOH + H₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
The molar mass of each compound is:
By reaction stoichiometry, the following amounts of mass of each compound participate in the reaction:
Then you can apply the following rule of three: if by reaction stoichiometry 13.88 g of Li produce 47.88 g of LiOH, 9.89 g of Li produce how much mass of LiOH?
[tex]mass of LiOH=\frac{9.89 g of Li*47.88 g of LiOH}{13.88 f of Li}[/tex]
Solving:
mass of LiOH= 34.12 grams
Finalli, 34.12 grams of LiOH are produced from 9.89 g of Li.
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