Respuesta :
Let Miguel has n nickels. Then, he has 9 - n quarters. A nickel is worth 5 cents and a quarter is worth 25 cents. For his combination of coins, his value is 125 cents. Mathematically, this is expressed as
5(number of nickels) + 25(number of quarters) = 125
5n + 25(9-n) = 125
5n - 25n + (25)(9) = 125
-20n + 225 = 125
-20n = -100
20n = 100
n = 5
So, Miguel has 5 nickels and 9 - 5 = 4 quarters.
5(number of nickels) + 25(number of quarters) = 125
5n + 25(9-n) = 125
5n - 25n + (25)(9) = 125
-20n + 225 = 125
-20n = -100
20n = 100
n = 5
So, Miguel has 5 nickels and 9 - 5 = 4 quarters.
Answer:
The answer 5 Nickels and 4 Quarters
Step-by-step explanation:
The reason for this answer is simple I will do the math real quick.
So you have 5 nickels right so 5(5) would be your equation which equals 25.
Alright so for the quarters the equation is 4(25) which equals 100.
Now if you take 100 and add 25 to it you will get 125 which means problem solved hope this helped.