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20-09-2021
Mathematics

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h(x) = ax^2 +1
Find the value of a when h(-2) = 21.

hx ax2 1 Find the value of a when h2 21 class=

Respuesta :

20-09-2021

Answer:

[tex]a = 5[/tex]

Step-by-step explanation:

Solving [tex]h(-2) = 21[/tex]:

[tex]h(-2) = 21 \\ a(-2)^2 +1 = 21 \\ a(4) +1 = 21 \\ 4a +1 = 21 \\ 4a +1 -1 = 21 -1 \\ 4a = 20 \\ \frac{4a}{4} = \frac{20}{4} \\ a = 5[/tex]

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