Answer:
3rd option
Step-by-step explanation:
Since the centre of dilatation is at the origin then multiply the coordinates by [tex]\frac{1}{3}[/tex]
K (- 3, 9 ) → K' (- 3([tex]\frac{1}{3}[/tex] ), 9([tex]\frac{1}{3}[/tex] ) ) → K' (- 1, 3 )
L (- 9, 0 ) → L' (- 9([tex]\frac{1}{3}[/tex] ), 0 ([tex]\frac{1}{3}[/tex] ) ) → L' (- 3, 0 )
M (2, - 8 ) → M' (2 ([tex]\frac{1}{3}[/tex] ), - 8 ([tex]\frac{1}{3}[/tex] ) ) → M' ( [tex]\frac{2}{3}[/tex] , - [tex]\frac{8}{3}[/tex] )
N (6, 4 ) → N' (6 ([tex]\frac{1}{3}[/tex] ) , 4 ([tex]\frac{1}{3}[/tex] ) ) → N' ( 2, [tex]\frac{4}{3}[/tex] )
