vrite on s margin. 2. A man left town M at 10:00 a.m. and travelled by car to town N at an average speed of 72 km/h. He spent 2 hours for a meeting and returned to town M by bus at an average speed of 40 km/h. If the distance covered by the bus was 2 km longer than that of the car and he arrived at town M at 1:55 p.m., calculate the distance from M to N.

Respuesta :

The distance from M to N is 48 km.

Since a man left town M at 10:00 a.m. and traveled by car to town N at an average speed of 72 km / h, and he spent 2 hours for a meeting and returned to town M by bus at an average speed of 40 km / h, to determine, if the distance covered by the bus was 2 km longer than that of the car and he arrived at town M at 1:55 pm, the distance from M to N, the following calculation must be performed:

  • 1:55 PM = 13:55
  • 13:55 - 10:00 = 3:55
  • 3:55 - 2:00 = 1:55
  • 60 = 100
  • 55 = X
  • 55 x 100/60 = X
  • 91.6 = X
  • Total time traveled by car and bus = 1,916 hours

  • 30/72 + 32/40 = 1,216
  • 40/72 + 42/40 = 1,605
  • 50/72 + 52/40 = 1,994
  • 45/72 + 47/40 = 1.8
  • 48/72 + 50/40 = 1,916

Therefore, the distance from M to N is 48 km.

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