The answer is "900, 1800, and 5800", and in this question, some of the data is missing so its a complete question and the solution can be defined as follows:
[tex]\bold{\text{m = matinee tickets}} \\\\\bold{\text{s = student tickets}}\\\\\bold{\text{r = regular tickets}}[/tex]
By given question, calculating equations are:
[tex]\to \bold{m + s + r = 8500}............................................(a)\\\\\to \bold{5m + 6s + 8.50r = 64600}............................(b)\\\\\to \bold{s = 2m}...................(c)[/tex]
Putting the equation (c) value in the equation (a) to calculate value:
[tex]m + 2m + r = 8500\\\\3m + r = 8500\\\\r = 8500 - 3m........................................(d)[/tex]
Putting equation (c) and (d) value into equation (b):
[tex]5m + 6(2m) + 8.50(8500 - 3m) = 64600\\\\5m + 12m + 72250 - 25.50m = 64600\\\\-8.50m = 64600 - 72250 \\\\-8.50m = -7650\\\\m = \frac{-7650}{-8.50}\\\\m = \frac{7650}{8.50}\\\\m = 900[/tex]
Putting m value into equation (c) and equation (d) to calculate its value:
Calculating the s value:
[tex]\to s = 2(900) \\\\ \to s = 1800[/tex]
Calculating the r value:
[tex]\to r = 8500 - 3(900) \\\\\to r = 8500 - 2700\\\\\to r = 5800\\\\[/tex]
So, the final value of "m, s, and r" are "900, 1800, and 5800".
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