Find the perimeter of a rectangle if the length is
6y + 10 and the width is y - 3

[tex]\implies \sf Perimeter = 2(L + W) \\ \implies \sf P= 2(6y + 10 + y - 3) \: units \\ \implies \sf P= 2(7y +7) \: units \\ \implies \red{\sf P= 14y + 14 \: units} \\ [/tex]

Therefore, perimeter is (14y + 14) units.

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BendingReality BendingReality · Answer 2 · 2022-01-12T14:40:30+01:00

Solution:-

We have been given to find out the perimeter of a rectangle who is having length (l) = 6y + 10 and width (w) = y - 3 i.e we have here,

Length (l) = 6y + 10

Width (w) = y - 3

The standard formula for calculating the perimeter of a rectangle is given by,

[tex]\implies\rm{p = 2(l + w)}[/tex]

[tex]\implies\rm{p = 2(6y + 10 + y - 3)}[/tex]

[tex]\implies\rm{p = 2(6y + y + 10 - 3)}[/tex]

[tex]\implies\rm{p = 2(7y + 7)}[/tex]

[tex]\implies\rm{p = 14y + 14}[/tex]

The perimeter of rectangle is 14y + 14 units.

Find the perimeter of a rectangle if the length is 6y + 10 and the width is y - 3

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Solution:-

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Find the perimeter of a rectangle if the length is
6y + 10 and the width is y - 3