Answer:
13.) [tex]x^0 = 123[/tex]°
14.) [tex]y^0 = 50[/tex]°
Step-by-step explanation:
13.) The given problem reflects an unknown value involving supplementary angles, in which the sum of the angles add up to 180°.
<ABD = 57
<DBC = [tex]x^0[/tex]
[tex]x^0 = 180 - 57[/tex]
[tex]x^0 = 123[/tex]°
14.) [tex]3y^0 = 150[/tex]° because they are vertical angles. By definition, vertical angles are congruent, share the same vertex, and must be nonadjacent.
< POS = [tex]3y^0[/tex]
< ROQ = 150°
Therefore, given that [tex]3y^0 = 150[/tex]°, we can solve for [tex]y^0[/tex] by dividing both sides of the equation by 3:
[tex]\frac{3y^0}{3} = \frac{150}{3}[/tex]
[tex]y^0 = 50[/tex]°
