Answer:
Guided Practice 4: QR = 7.12
Guided Practice 5: x = 15
Step-by-step explanation:
Guided Practice 4:
Given that:
PR = [tex]13 \frac{3}{4} ft = 13.75 ft[/tex]
PQ = [tex]6\frac{5}{8} ft = 6.63ft[/tex]
QR = ?
PQ + QR = PR
6.63 + QR = 13.75
Subtract 6.63 from both sides of the equation to solve for QR:
6.63 - 6.63 + QR = 13.75 - 6.63
QR = 7.12
Check if QR is valid:
PQ + QR = PR
6.63 + 7.12 = 13.75
13.75 = 13.75 (true statement).
Guided Practice 5:
Given that:
AC = 4x - 12
AB = x
BC = 2x + 3
AB + BC = AC
x + (2x + 3) = 4x - 12
Combine like terms:
3x + 3 = 4x - 12
Add 12 on both sides of the equation:
3x + 3 + 12 = 4x - 12 + 12
3x + 15 = 4x
Subtract 3x from both sides of the equation:
3x - 3x + 15 = 4x - 3x
15 = x
Check if AB = x is valid by plugging in 15 to x values in the equation:
AB + BC = AC
15 + 2(15) + 3 = 4(15) - 12
15 + 30 + 3 = 60 - 12
48 = 48 (True statement)
