We have that the radius of the disk in centimeters.
[tex]R=6.3cm[/tex]
From the question we are told
Generally the equation for Potential energy at disk center is mathematically given as
[tex]Ve=\int^{H}_0 \frac{2\pi rdr}{r}\\\\Ve=2Ak\pi \int^{H}_0 rdr\\\\Ve=Ak\piR^2[/tex]
Therefore
[tex]R=\frac{Ve}{Ak\pi}\\\\R=\frac{84.4*10^{-3}}{7.55*10^{-10*8.99*10^9\pi}}\\\\R=6.3*10^{-2}m[/tex]
Therefore the radius of the disk in centimeters.
[tex]R=6.3*10^{-2}m[/tex]
[tex]R=6.3cm[/tex]
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