The mass of sulfur in 49.5 g of CaSO₄ is 11.7 g.
A 23.9 g sample of CaSO₄ is found to contain 7.04 g of Ca and 11.2 g of O. Considering that the sum of the masses of the elements is equal to the mass of the compound, the mass of S in 23.9 g of CaSO₄ is:
[tex]mCaSO_4 =mCa + mS + mO\\mS = mCaSO_4 - mCa - mO\\mS = 23.9g - 7.04 g - 11.2 g = 5.66 g[/tex]
There are 5.66 g of S in 23.9 g of CaSO₄. The mass of S in 49.5 g of CaSO₄ is:
[tex]49.5 g CaSO_4 \times \frac{5.66gS}{23.9 g CaSO_4} = 11.7 g S[/tex]
The mass of sulfur in 49.5 g of CaSO₄ is 11.7 g.
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