look at the attachment
- Length of rod given by f/2
Radius of the culvature=2f
Now
- Object distance =PC-AB=2f-f/2=4f-f/2=-3f/2
Applying Mirror formula
[tex]\\ \rm\longmapsto \dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}[/tex]
[tex]\\ \rm\longmapsto \dfrac{1}{v}=\dfrac{1}{u}+\dfrac{1}{f}[/tex]
[tex]\\ \rm\longmapsto \dfrac{1}{v}=\dfrac{1}{-3f/2}+\dfrac{-1}{f}[/tex]
[tex]\\ \rm\longmapsto \dfrac{1}{v}=-\dfrac{2}{3f}-\dfrac{1}{f}[/tex]
[tex]\\ \rm\longmapsto \dfrac{1}{v}=\dfrac{2-3}{3f}[/tex]
[tex]\\ \rm\longmapsto \dfrac{1}{v}=\dfrac{-1}{3f}[/tex]
[tex]\\ \rm\longmapsto v=-3f[/tex]
Now
[tex]\\ \rm\longmapsto m=\dfrac{h'}{h}=-\dfrac{v}{u}=[/tex]
[tex]\\ \rm\longmapsto m=\dfrac{f}{f/2}[/tex]
[tex]\\ \rm\longmapsto m=2[/tex]
