Respuesta :
Answer:
The six trig ratios at 3pi/2 are:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2) (undefined)
csc(3pi/2)=-1
sec(3pi/2) (undefined)
cot(3pi/2)=0
Step-by-step explanation:
If tangent is undefined then cosine would have to be 0 given that tangent is the ratio of sine to cosine.
cosine is 0 at pi/2 and 3pi/2 in the first rotation of the unit circle.
3pi/2 satisfies the given constraint.
The six trig ratios are therefore:
sin(3pi/2)=-1
cos(3pi/2)=0
tan(3pi/2)=-1/0 (undefined)
Reciprocal values:
csc(3pi/2)=-1
sec(3pi/2) undefined since cos(3pi/2)=0
cot(3pi/2)=0/-1=0
Answer:
Step-by-step explanation:
tan θ is undefined at θ=π/2 and 3π/2
sin π/2=1
cos π/2=0
tanπ/2=undefined
csc π/2=1
sec π/2= undefined
cot π/2=0
sin 3π/2=sin (π+π/2)=-sin π/2=-1
cos 3π/2=cos (2π-π/2)=cosπ/2=0
tan (3π/2)=tan (π+π/2)=tanπ/2=undefined
csc 3π/2=csc (π+π/2)=-csc π/2=-1
sec 3π/2=sec(2π-π/2)=secπ/2=undefined
cot 3π/2=cot(π+π/2)=cotπ/2=0
