A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by given equation. Using this equation, find the time that rocket will hit the ground, to the nearest 100th of second. Y=-16x^2+157x+104

A rocket is launched from a tower The height of the rocket y in feet is related to the time after launch x in seconds by given equation Using this equation find class=

Respuesta :

The time that rocket will hit the ground, to the nearest 100th of second is 10.43 seconds

Given the equation representing the height reached by a rocket as:

[tex]y = -16x^2 + 157x + 104[/tex]

The rocket will hit the ground when y = 0. Substituting y = 0 into the expression to get x;

[tex]0 = -16x^2 + 157x + 104\\16x^2 - 157x - 104 = 0\\[/tex]

On factorizing:

x = 10.43 seconds

Hence the time that rocket will hit the ground, to the nearest 100th of second is 10.43 seconds

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