Answer:
5 < √(29) < 6
Step-by-step explanation:
1. First, we have to square the square root of 29.
- [tex]\sqrt{29^2}[/tex]
- [tex]29[/tex]
2. Alright, so now we know that the two digits when squared have 29 between them. Now, we have to find the digits.
3. When 5 is squared, we get 25. When 6 is squared, we get 36. This means that 29 is between 25 and 36, and we can write it as this statement: [tex]25 < 29 < 36[/tex].
4. Since the question is asking which two integers complete the statement, we just have to square root all the numbers.
- [tex]\sqrt{25} < \sqrt{29} < \sqrt{36}[/tex]
- [tex]5 < \sqrt{29} < 6[/tex]
Therefore, the answer is 5 < √(29) < 6.
