The magnitude of the force exerted by the fish is 3,052.5 N.
The given parameters;
- mass of the reel, m = 652 g = 0.652 kg
- diameter of the reel, d = 10 cm
- radius of the reel, r= 5 cm = 0.05 m
- angular speed of the reel, ω = 306 rad/s
According to Newton's third law, the force exerted by the reel is equal in magnitude to the force fish exerted on the reel.
The centripetal force of the reel = force exerted by the fish
[tex]F_c = m\omega^2 r\\\\F_c = 0.652 \times (306)^2 \times 0.05\\\\F_c = 3,052.5 \ N[/tex]
Thus, the magnitude of the force exerted by the fish is 3,052.5 N.
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