A cylinder contains water to a level of 15.5. 20.0 grams of copper is dropped in. What will be the new height of the water? (Density of copper 8.96g/ml)

Respuesta :

The new height of the water is 17.7 mL

The density of a substance is simply defined as mass per unit volume of the substance. Mathematically, it is expressed as:

Density = mass / volume

With the above formula, we can obtain the volume of the copper. This can be obtained as follow:

Mass of copper = 20 g

Density of copper = 8.96 g/mL

Volume of copper =?

Density = mass / volume

8.96 = 20 / volume

Cross multiply

8.96 × Volume = 20

Divide both side by 8.96

Volume = 20 / 8.96

Volume of copper = 2.2 mL

Finally, we shall determine the new height of the water. This can be obtained as follow:

Initial height of water = 15.5 mL

Volume of copper = 2.2 mL

New height of water =?

New height of water = (Initial height of water) + (Volume of copper)

New height of water = 15.5 + 2.2

New height of water = 17.7 mL

Therefore, the new height of the water is 17.7 mL

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