There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.
[tex]2N_2+3H_2\rightarrow 2NH_3[/tex]
To find:
Bonds on the reactant side
Solution:
[tex]2N_2+3H_2\rightarrow 2NH_3[/tex]
Reactants in the reaction = [tex]N_2, H_2[/tex]
The bond between nitrogen atoms in single [tex]N_2[/tex] molecule = N≡N (triple bond)
Then in two [tex]N_2[/tex] molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single [tex]H_2[/tex] molecule = H-H (single bond)
Then in three [tex]H_2[/tex] molecules = 3 H-H (single bonds)
Product in the reaction =[tex]NH_3[/tex]
The bonds between nitrogen and hydrogen atoms in single [tex]NH_3[/tex] molecule = 3 N-H (single bond)
Then in two [tex]NH_3[/tex] molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
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