The equation of the line j perpendicular to the given line is 2y + x = 6
Given the equation for line k expressed as y = 2x+8
Slope of the line is expressed as:
mx = 2x
m = 2
The equation of the line j perpendicular to the line will be in the form;
y-y0 = m(x-x0)
Slope of line j = -1/2
Point (x0, y0) = (0, 3)
Substitute the points and the slope into the formula
y - 3 = -1/2(x-0)
2(y - 3) = -x
2y - 6 = -x
2y + x = 6
Hence the equation of the line j perpendicular to the given line is 2y + x = 6
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