200 mg of C₃₂H₃₄N₆O₁₀ contains 116 mg of carbon.
To obtain the answer to the question, we'll begin by calculating the molar mass of C₃₂H₃₄N₆O₁₀. This can be obtained as follow:
Molar mass of C₃₂H₃₄N₆O₁₀ = (12×32) + (1×34) + (14×6) + (16×10)
= 384 + 34 + 84 + 160
= 662 g/mol
From the molar mass of C₃₂H₃₄N₆O₁₀, we can see that:
662 g of C₃₂H₃₄N₆O₁₀ contains 384 g of carbon.
Converting 662 g of C₃₂H₃₄N₆O₁₀ to mg, we have
1 g = 1000 mg
Therefore,
662 g = 662 × 1000
662 g of C₃₂H₃₄N₆O₁₀ = 662000 mg
Converting 384 g of carbon to mg, we have,
1 g = 1000 mg
Therefore,
384 g = 384 × 1000
384 g of carbon = 384000 mg
Thus, we can say that:
662000 mg of C₃₂H₃₄N₆O₁₀ contains 384000 mg of carbon.
Finally, we shall determine the mass (in mg) of carbon in 200 mg of C₃₂H₃₄N₆O₁₀. This can be obtained as follow:
662000 mg of C₃₂H₃₄N₆O₁₀ contains 384000 mg of carbon.
Therefore, 200 mg of C₃₂H₃₄N₆O₁₀ will contain = [tex]\frac{200 * 384000}{662000}[/tex] = 116 mg of carbon.
Thus, we can conclude that 200 mg of C₃₂H₃₄N₆O₁₀ contains 116 mg of carbon.
Learn more: https://brainly.com/question/24572517
