2.Suppose P(C) = 1/7; P(D) = 7/10; and P(C or D) = 3/4.
Find P(C and D).
Can this really be a probability? If not, explain why not. (If it is, make certain that it is in
simplified form.

Respuesta :

Probabilities are used to determine the chance of an event.

  • The value of P(C and D) is [tex]\frac{13}{140}[/tex]
  • It can be a probability

Given

[tex]P(C) = \frac 17[/tex]

[tex]P(D) = \frac 7{10}[/tex]

[tex]P(C\ or\ D) = \frac 34[/tex]

P(C and D)

To calculate P(C and D), we make use of:

[tex]P(C\ and\ D) = P(C) + P(D) - P(C\ or\ D)[/tex]

So, we have:

[tex]P(C\ and\ D) = \frac 17 + \frac 7{10} - \frac 34[/tex]

Take LCM

[tex]P(C\ and\ D) = \frac{20+98-105}{140}[/tex]

[tex]P(C\ and\ D) = \frac{13}{140}[/tex]

Can it be a probability?

All the given probabilities and the calculated probability, P(C and D) are between 0 and 1.

This means that, it can be a probability.

Read more about probabilities at:

https://brainly.com/question/24297863

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