We have that the estimated the current density in copper wire at 20 °C is
[tex]J=38*10^6A/m^2[/tex]
From the question we are told
- the current density in copper wire at 20 °C
- if an electric field of 0.923 V/m exists within the wire
Generally the equation for the current density is mathematically given as
current density
[tex]J=\alpha E[/tex]
Where
[tex]\alpha=\frac{1}{e}\\\\\\alpha=\frac{1}{2.44*10^{-8}}\\\\\alpha=4.09*10^7[/tex]
Therefore
[tex]J=4.09*10^7* 0.923[/tex]
[tex]J=38*10^6A/m^2[/tex]
For more information on this visit
https://brainly.com/question/20459283?referrer=searchResults
