A shunting engine in a rail yard is working on a straight east-west section of line. First it travels west for 150 s with an average velocity of 4 m/s, to hook up to 10 empty freight cars. Then it pulls the cars east with an average velocity of 3 m/s for 200 s, to a loading area. Calculate the engine's final displacement.

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Аноним Аноним · Answer 1 · 2021-09-19T08:54:50+02:00

Displacement-1

[tex]\\ \rm\longmapsto Velocity(Time)[/tex]

[tex]\\ \rm\longmapsto 150(4)[/tex]

[tex]\\ \rm\longmapsto 600m[/tex]

Displcaement-2

[tex]\\ \rm\longmapsto 200(3)[/tex]

[tex]\\ \rm\longmapsto 600m[/tex]

Total displacement=600+600=1200m

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Sᴘᴀᴄᴇ7 Sᴘᴀᴄᴇ7 · Answer 2 · 2021-10-20T10:30:40+02:00

Answer:

[tex]\sf\longmapsto \: 1200 \: m[/tex]

Explanation:

First, Let's solve Displacement 1

We know , Velocity × time

Let's start solving Displacement 1

[tex]\sf\longmapsto \: 150 \times 4\:m[/tex]

[tex]\sf\longmapsto \: 600 \: m[/tex]

Now, let's solve displacement 2

[tex]\sf\longmapsto \:200 \times 3\:m [/tex]

[tex]\sf\longmapsto \: 600 \: m[/tex]

Now, the final step is to add displacement 1 and displacement 2.

Why addition?

As nothing is mentioned to subtract or divide or multiply or addition.So we have to add.

[tex]\sf\longmapsto \: 600 + 600 = 1200 \: m[/tex]

Hence the engine's final displacement is 1200 m