[tex]x = 10[/tex]
Given:
[tex]\frac{x -1}{3} = k \text{ where } k = 3[/tex]
Solving for [tex]x[/tex]:
[tex]\frac{x -1}{3} = k \text{ where } k = 3\\ \frac{x -1}{3} = 3 \\ \frac{x -1}{3} \cdot 3 = 3 \cdot 3 \\ x -1 = 9 \\ x -1 +1 = 9 +1 \\ x = 10[/tex]
[tex] \large \frac{x - 1}{3} = k \: and \:k = 3 [/tex]
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[tex]\large\bf{\underline{Putting\: the\:value\:of\:k}}[/tex]
[tex]⟹ \large \frac{x - 1}{3} = 3[/tex]
[tex]⟹\large {x - 1 = 3 \times 3}[/tex]
[tex]⟹\large{x = 9 + 1}[/tex]
[tex]⟹\large{x = 10}[/tex]
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[tex]\large\bf{\underline{Hence}}[/tex]
[tex]\huge{⟹x = 10}[/tex]
