The combustion of glucose, C6H1206(s), produces carbon dioxide, CO2(g), and water, H2O(g), according to the
equation below.
CoH1206(s) +602(g) → 6CO2(g) + 6H2O(1)
The enthalpy of the reaction is -2,840 kJ. What is the heat of combustion, per mole, of glucose?
✓-2,840 kJ/mol
473.3 kJ/mol
473.3 kJ/mol
* 2,840 kJ/mol
See