If A=1. B=1/2. C=-1. R=1/3 S=1/4
Solve: step by step explain!

Answer:
[tex] \frac{1}{12} [/tex]
Step-by-step explanation:
[tex] \frac{ {c}^{2} }{3 \: . \: {b}^{ - 2} } \\ \frac{ {1}^{2} }{3 \: . \: { (\frac{1}{2}) }^{ - 2} } \\ \frac{1}{3 \: . \: \frac{1}{ {( \frac{1}{2}) }^{2} } } \\ \frac{1}{3 \: . \: \frac{1}{ \frac{1}{4} } } \\ \frac{1}{3 \: . \: 1 \: . \: 4} \\ \frac{1}{12} \\ [/tex]
[tex] \frac{1}{3 \: . \: \frac{1}{ \frac{1}{4} } } \\ \frac{1}{3 \: . \: 1 \div \frac{1}{4} } \\ \frac{1}{3 \: . \: 1 \: . \: 4} \\ \frac{1}{12} [/tex]