Si se dispone de 123,11g de cloruro de plata (AgCl),¿cuantos moles contiene el frasco?
¿cual es el número total de atomos de cloro presente?

Respuesta :

JohnES
Masa molecular del Cloruro de plata,

Mm=107.9+35.5=143.4 g/mol

El número de moles es,

n=M/Mm=123.11/143.4=0.161 mol

El número total de átomos de cloro es,

N=0.161*Número de Avogadro=9.7*10^22 átomos

In the case above. The total number of chlorine atoms is, N=0.161* Avogadro's number=9.7*10^22 atoms

What is the statement about?

The translation is "If 123.11 g of silver chloride (AgCl) are available, how many moles does the bottle contain? What is the total number of chlorine atoms present?"

Masa molecular del Cloruro de plata,

Note that Mm =107.9+35.5

= 143.4 g/mol

El número de moles es,

n=M/Mm=123.11/143.4

=0.161 mol

El número total de átomos de cloro es,

N=0.161*

Número de Avogadro=9.7*10^22 átomos

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