9 g of beryllium (Be) and 4 g of Helium (He) have the same number of particles.
If you have 9 g of beryllium (Be) and 4 g of Helium (He), what do both have in common?
The density of Be is 1.84 g/mL. The volume of 9 g of Be is:
[tex]9g \times \frac{1mL}{1.84g} = 4.9 mL[/tex]
The density of He is 0.18 g/L. The volume of 4 g of He is:
[tex]4 g \times \frac{1L}{0.18g} = 22 L[/tex]
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They have nothing in common. NO
- Same number of particles. YES
The molar mass of Be is 9 g/mol and the molar mass of He is 4 g/mol. Then, we have 1 mole of each one (6.02 × 10²³ particles)
The molecular weight of Be is 9 amu and the molecular weight of He is 4 amu.
9 g of beryllium (Be) and 4 g of Helium (He) have the same number of particles.
You can learn more about moles here: https://brainly.com/question/20486415
