AbandonedAllenTheBro AbandonedAllenTheBro

18-12-2016
Mathematics

contestada

Carmen enters a painting in an art contest. The contest rules say that all paintings must be rectangular, with an area no greater than 3,003.04 cm2. Carmens painting is 16 cm wide. What is the greatest length the painting can have and still have an area within the contest rules?

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texaschic101 texaschic101

18-12-2016

A = LW

3,003.04 = 16L
3,003.04 / 16 = L
187.69 = L

so the painting can be 187.69 cm in length

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alchesna alchesna

18-12-2016

To answer you question, you must divide 3,003.04 cm^2 by 16 cm. You will get 187.69 cm, which means you solved it correctly

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