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Which logarithmic equation is equivalent to the exponential equation below?
E^a=38.47

A. In a=38.47
B. Log a 38.47=3.65
C. In 38.47= a
D. Log38.47 3.65=e

Respuesta :

C is the correct answer

Answer:

C)  a =  ln (38.47).

Step-by-step explanation:

Given : [tex]E^{a}[/tex] = 38.47

To find : Which logarithmic equation is equivalent to the exponential equation.

Solution : We have given that : [tex]E^{a}[/tex] = 38.47.

Taking natural logarithm both sides

[tex]log_{e}(E^{a})[/tex] = log(38.47).

By the  logarithm rule: [tex]log_{a}(a^{n})= n[/tex] ; [tex]log_{e}(e) = 1.[/tex]=1.

Then , a =  ln (38.47).

Therefore,C)  a =  ln (38.47).

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